Two particles execute simple harmonic motion along the same straight line with same amplitude and 'same frequency. The two particles pass one another when moving in opposite directions each time at a distance of 
times the amplitude from their common mean position. The phase difference between the two particles is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Position of particle 1, 
Position of particle 2, 
let particle 1 is moving away from mean position
Given, 
let particle 2 is moving towards mean position,
Phase difference, 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A particle initially at the mean position is executing simple harmonic motion with an angular frequ…
A particle is executing simple harmonic motion. If the minimum time taken by the particle to move f…
Under the action of a force where is in Newton and is in meters, an object of mass executes sim…
The displacement of a particle is given by the relation . The amplitude of the particle is
A point mass oscillates along -axis according to . If the acceleration of the point mass is writt…
A particle performs simple harmonic motion with a time period of . At a time , the particle passe…